list_files()

directory.list_files()

Get a list of files in directory (from your Diffgram service).

Parameters:
  • page_num: the page number to fetch from the file list. Default is 1.
  • limit: number of elements per page, Defaults to 25
  • search_term: a string to search for a specific file.
  • file_view_mode: a string that represents serializable data to include. Defaults to annotation. You can use value base to get a smaller serializable version of the file with no annotations to improve performance.
file_object_list = directory.list_files()

Usage Example:

import logging
from diffgram import Project
project_literal = Project() # TODO add auth
dataset = project_literal.directory.get(name = "dataset_name")	# TODO add name
logging.basicConfig(level=logging.INFO)		# Optional, to show ID

file_list = dataset.list_files()

print("Length", len(file_list))
for file in file_list:
    print(file.id)
    print(file.original_filename)

Returns

INFO:root:Using Dataset ID 85855
Length 122
23231222
...
file_name
...

Pagination on List Files

If you want to access more than one page of the file_list, you can use the dataset.file_list_metadata dictionary to get the current page number and iterate over all the available pages.

dataset_default = project.directory.get(name = "Default")

page_num = 1
all_files = []
while page_num != None:
  print('Current page', page_num)
  diffgram_files = dataset_default.list_files(limit = 1000, page_num = page_num, file_view_mode = 'base')
  page_num = dataset_default.file_list_metadata['next_page']
  print('Page {} of {}'.format(page_num, dataset_default.file_list_metadata['total_pages']))
  all_files = all_files + diffgram_files